Use the three steps to solve the problem. the length of a rectangle is 2 inches less than 3 times the number of inches in its width. if the perimeter of the rectangle is 28 inches, what is the width and length of the rectangle?

Let the width of the rectangle be w.

Let the length be l.

l = 3w - 2

Given,

Perimeter = 28 

2*( l + w ) = 28

2*( 3w -2 + w ) = 28 

4w - 2 = 14  [ Dividing both sides by 2 ]

2w - 1 = 7 [ Dividing both sides by 2 ]

2w = 8

w = 4.

Thus,

l = 3w -2 = 3*4 - 2 = 12 - 2 = 10

Therefore, the length is 10 inches and the width is 4 inches.

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