Mathematics, 22.11.2019 14:31 sarah192002

The rule t1, -4 ro, 180°(x, y) is applied to rectangle klmn. which rectangle shows the final image? ?

The rule t1, -4 ro, 180°(x, y) is applied to rectangle klmn. which rectangle shows the final image?

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Answer from: yunilka28

Figure 3.

Step-by-step explanation:

We perform the rotation first. A 180° rotation about the origin maps every point

(x, y)→(-x, -y). This means it negates both the x- and y-coordinates.

The pre-image points are:

K(3, -4); L(3, -1); M(5, -1); N(5, -4). Performing the rotation and negating the coordinates will give us:

K'(-3, 4); L'(-3, 1); M'(-5, 1); N'(-5, 4).

Now we perform the translation. The translation rule is <1, -4>; this means we add 1 to each x-coordinate and subtract 4 from each y-coordinate. This maps to our new points:

K''(-2, 0); L''(-2, -3); M''(-4, -3); N''(-4, 0)

These are the points of figure 3.

Answer from: melodyfigueroa44

Let me help you!

Looking at the visual, we can see five figures: KLM, 1, 2, 3, and 4.
Applying the rule T1, -4 RO, 180°(x, y) to rectangle KLMN - without even solving - just by merely observing, we can say (without a doubt) that the rectangle KLMN will most likely fall in the negative axis.

First rotation: -4 to the left.
Second rotation: -4 to the left.
Last rotation: -4 to the left making the last figure 3. < What we are looking for!

Therefore, the rectangle which shows the final image is figure 3 or rectangle 3.

Answer from: Quest

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

Answer from: Quest

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

= $\sqrt{(9-6)^{2} +(12-6)^{2} } \\=\sqrt(45)=3\sqrt(5)$

side j'k'=distance between j' and k'

= $\sqrt{(3-2)^{2} +(2-4)^{2} } \\=sqrt(5)$

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

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