How many solutions does a triangle with side lengths a=4, a=68 degrees, and b=10 have?

2 possible solutions

Step-by-step explanation:

First we need to construct the three different triangles, shown in the image.

After we put the equations for each triangle:

Triangle 1:

Triangle 2:

Triangle 3:

As all are quadratic equations, so we resolve them with the general formula for quadratic equations, then we have 6 numerical solutions, but we can only consider those that are positive and real.

For triangle 1:

For triangle 2:

For triangle 3:

So, with the previous results, the only ones that are possible to construct a triangle are:

Triangle 1: because is positive

Triangle 2: because is positive

Triangle 3: None as both are imaginary

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure