In physics, if a moving object has a starting position at s 0, an initial velocity of v 0, and a constant acceleration a, then the position s at any time t > 0 is given by:

s = at 2 + v 0 t + s 0.

solve for the acceleration, a, in terms of the other variables. for this assessment item, you can use ^ to show exponents and type your answer in the answer box, or you may choose to write your answer on paper and upload it.

Actually the position function with respect to time under constant acceleration is:

a=g

v=⌠g dt

v=gt+vi

s=⌠v

s=gt^2/2+vit+si

So if vi and si are zero then you just have:

s=gt^2/2

Notice that it is not gt^2 but (g/2) t^2

So the first term in any quadratic is half of the acceleration times time squared because of how the integration works out...

Anyway

sf=(a/2)t^2+vit+si

(sf-si)-vit=a(t^2)/2

2(sf-si)-2vit=at^2

a=(2(sf-si)-2vit)/t^2  and if si and vi equal zero

a=(2s)/t^2

I’m sorry i can’t u