Enrique weighs 5 pounds more than twice brendan's weight. if their total weight is 225 pounds, how much does enrique weigh?

E=2b+5  solve for b, subtract 5 from both sides

e-5=2b  divide both sides by 2

b=(e-5)/2, then we are told that:

e+b=225, using b found above in this equation yields:

e+(e-5)/2=225   making both terms on left have a common denominator of 2

(2e+e-5)/2=225 multiply both sides by 2

2e+e-5=450  combine like terms on left side

3e-5=450  add 5 to both sides

3e=455  divide both sides by 3

e=455/3

e=151 2/3   

So Enrique weighs 151 2/3 pounds  (Brendan weighs 73 1/3 pounds)

Hello!

We know that their total weight is 225, so we know that's on one side of the equation, alone. 

We have 225. 
B (Brendon's weight) + E (Enrique's weight)=225

We know that Enrique weighs 5 pounds more than twice Brendan's weight. 

So Enrique's weight is

E = 5 + 2B (5 more pounds than twice Brendan's weight)

So now we plug the E into our first equation. 

B + (5 + 2B) = 225

Simplify. 

3B + 5 = 225

Subtract 5 from both sides. 

3B = 220

Divide by 3

B = 73.3

Now we'll plug E and B into the initial equation to see if we're correct. 

73.3 + [5 + 2(73.3)] = 225

Simplify

73.3 + (5 + 146.7) = 225

So Yes, based on what we have done, Brendan weighs 73.3 pounds, and Enrique weighs 151.7 pounds. 

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