Simplify 2(f^4)^2 f^3 divided by 6f^9

((2f^4)^2*f^3)/(6f^9)

pertinent rules of exponents:

(a^b)^c=a^(b*c),  (a^b)(a^c)=a^(b+c), and (a^b)/(a^c)=a^(b-c) so

(2f^(4*2)*f^3)/(6f^9)

(2f^8*f^3)/(6f^9)

(2f^(8+3))/(6f^9)

(2f^11)/(6f^9)

(2/6)(f^11/f^9)

(1/3)(f^(11-9)

(1/3)(f^2)

(f^2)/3

The scale factor of what ?

Idon’t know but you’ll figure it out