Apallet stacked with bags of cement weighing a total of 5501 n must be pushed up a 2.30-m incline to a 75.0-cm high platform. what force, in newtons, must be applied to get the job done?

Assume that the incline is frictionless.
Refer to the diagram shown below.

Note that 75 cm = 0.75 m.
Therefore the angle of the incline is given by
sin(x) = 0.75/2.3 = 0.3261.

The weight pushed up the incline is  W = 5501 N.
The component of the weight acting down the incline is
W*sin(x) = 5501*0.3261 = 1793.9 N

The force, F, should overcome this weight acting along the incline, therefore
F = 1794 N (nearest integer)

 1794 N