How does the volume of an oblique cone change if the height is reduced to 2/5 of its original size and the radius is doubled?

Given that the height is reduced by 2/5 and the radius is doubled, the new volume will be given by:
V=1/3πr^2h
r=2r
h=2/5h
thus;
V=1/3*π*(2r)^2(2/5h)
=8/15πr^2h
This implies that the new volume will be 8/15 of the original volume