Which of the following is an extraneous solution of sqrt(-3x-2)=x+2 a.-6 b.-1 c.1 d.6

- 6 is the extraneous solution.

Step-by-step explanation:

Given : .

To find : Which of the following is an extraneous solution .

Solution : We have given that .

Taking square both sides

-3x - 2 = .

On applying identity   = a² + b² + 2ab

Then ,

-3x -2 =  x² + 2² + 2 * 2 *x

-3x -2 =  x² + 4 + 4x.

On adding both sides by 3x

-2 =  x² + 4 + 4x + 3x

-2 =  x² + 4 + 7x

On adding both sides by 2

0 =  x² + 4 + 7x + 2

On switching sides

x² +7x + 6 = 0

On Factoring

x² +6x + x + 6 = 0

x ( x+ 6 ) +1 (x +6 ) = 0

On grouping

( x +1) ( x +6) = 0

x = -1, -6.

Let check for x = -6

.

4 =  -4

An extraneous solution is a root of a transformed equation that is not a root of the original equation.

Therefore,  -6 is the extraneous solution.

yor answer is 7/6 times 5

step-by-step explanation:

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: