Acountry population in 1993 was 94 million. in 1999 it was 99 million. estimate the population in 2005 using the expoetential growth formula. round your answer to the nearest million

First find the rate of growth
The formula is
P=Ae^rt
P 99 million
A 94 million
E constant
R rate of growth?
T time 1,999−1,993=6 years
Solve the formula for r
R=[log (p/A)÷log (e)]÷t
R=(log(99÷93)÷log(e))÷6
R=0.01

the population in 2005
P=Ae^rt
T time 2,005−1,993=12 years
P=93×e^(0.01×12)
P=105 million

Where are the answer choices?

You're gonna need to post the table