Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. the average basketball player is 79 inches tall. approximately what percent of the adult male population is taller than the average basketball player? 0.135% 0.875% 49.875% 99.875%

A. 0.135%

Step-by-step explanation:

We have been given that adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall.  

We need to find the area of normal curve above the raw score 79.

First of all let us find the z-score corresponding to our given raw score.

, where,

,

,

,

.

Upon substituting our given values in z-score formula we will get,

Now we will find the P(z>3) using formula:

Using normal distribution table we will get,

Let us convert our answer into percentage by multiplying 0.00135 by 100.

Therefore, approximately 0.135% of the adult male population is taller than the average basketball player and option A is the correct choice.

step-by-step explanation: