Here we want to find all the zeros of the function f(x) = 16*x^4 - 81.
The zeros are:
x = 3/2x = -3/2x = (3/2)*ix = (-3/2)*i
First, for a given function f(x), we define the zeros as the values of x such that:
f(x) = 0.
Then we must solve:
f(x) = 16*x^4 - 81 = 0
Solving this for x leads to:
16*x^4 = 81
x^4 = 81/16
x^2 = ±√(81/16) = 9/4
x = ±√±(9/4) = ±3/2 and ±(3/2)*i
So there are 4 zeros, and these are:
x = 3/2x = -3/2x = (3/2)*ix = (-3/2)*i
Where the two complex zeros come from evaluating the second square root on -9/4.
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