how can one thirdx − 2 = one fourthx + 11 be set up as a system of equations?

3y − x = −6
4y − x = 44

3y + x = −6
4y + x = 44

3y − 3x = −6
4y − 4x = 44

3y + 3x = −6
4y + 4x = 44

Hello!

we have that:

one third x − 2 = one fourth x + 11

this means:

(1/3)x - 2 = (1/4)x + 11

if this are equal numbers, we can write it as:

(1/3)x - 2 = y =  (1/4)x + 11

now we have the system of equations:

(1/3)x - 2 = y

(1/4)x + 11 = y

if we "simplify" the rational therm in each equation, we get:

3*(1/3)x - 3*2 = 3y

x - 6 = 3y

and

4*(1/4)x + 4*11 = 4y

x + 44 = 4y

Then our system of equations is:

x - 6 = 3y

x + 44 = 4y

Now we can subtract x in each side of both equations:

-6 = 3y - x

44 = 4y - x

Then the right option is the first one.

3y - x = -6

4y - x = 44

ok

step-by-step explanation:

sine

step-by-step explanation: