What is the equation of the line in slope-intercept form that is perpendicular to the line y = x – 2 and passes through the point (–12, 10)? y = x – 6 y = x + 6 y = x + 26 y = x + 10

The slope of the given line   y = x – 2   is 1.  Therefore, the slope of a line perpendicular to  y = x – 2   is -1/1, or just -1.

In point-slope form, the equation of the new line is 

y-10 = -1(x-[-12]), or            y-1 = -(x+12)          or   y-1 = -x - 12, or
                                                                                 y = -x - 11.

The answer is poppy pants69