Abcd is a quadrilateral inscribed in a circle, as shown below:

circle o is shown with a quadrilateral abcd inscribed inside it. angle a is labeled x plus 16. angle b is labeled x degrees. angle c is labeled 6x minus 4. angle d is labeled 2x plus 16.

what equation can be used to solve for angle d?

(2x + 16) + (6x − 4) = 90
(x + 16) − (x) = 90
(x + 16) + (2x + 16) = 180
(2x + 16) + (x) = 180

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

the answer is b.6

step-by-step explanation: