What is the probability of rolling a number less than or equal to 8 with the sum of two dice, given that at least one of the dice must show a 6?

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

range is infinite on both x and y axis positive and negative

step-by-step explanation: