The sum of 4 consecutive integers is 130. what is the third number in the sequence?

The third number in the sequence 31, 32, 33, 34 is 33

Step-by-step explanation:

let first number be the smallest number be x.

Consecutive numbers are those numbers that follow each other in order and they should have a difference of 1 between every two numbers.

Then, the four consecutive integers are x , (x+1), (x+2) , (x+3)

Given: the sum of 4 consecutive integers is 130.

From the given condition we have,

Like terms states that contain the same variables raised to the same power.

Combine like terms we get,

Subtract 6 from both the sides, we get

Simplify we get,

Divide both sides by 4;  

On simplify we get, the value of x i.e,

the sequence we have, 31, 32, 33, 34,

therefore, the third number in the sequence is, 33.

The answer is 33.

Step-by-step explanation:

I got this answer on Khan Academy.

Hope this helps! :)

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345

12

step-by-step explanation: