⦁the point guard of a basketball team has to make a decision about whether or not to shoot a three-point attempt or pass the ball to another player who will shoot a two-point shot. the point guard makes three-point shots 30 percent of the time, while his teammate makes the two-point shot 48 percent of the time. xi 3 0 p(xi) 0.30 0.70 xi 2 0 p(xi) 0.48 0.52 ⦁ what is the expected value for each choice? ⦁ should he pass the ball or take the shot himself? explain

The given data is

Pr(xi)=0.3*0.70

The expected value =0.90

Where as we calculated the probability=0.96

As 0.96>0.9

So he should pass the ball as probability is greater.

2? if not the correct answer you might need to provide more information

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°