Mrs. ming invested an amount of money in two accounts for one year. she invested some at 8% interest and the rest at 6% interest. her total amount invested was $1,500. at the end of the year, she had earned $106.40 in interest. how much had mrs. ming invested in the account paying 6%?
a.$117
b.$680
c.$760
d.$820

The correct option is B.

Step-by-step explanation:

It is given that Mrs. Ming invested an amount of money in two accounts for one year.She invested some at 8% interest and the rest at 6% interest. Her total amount invested was $1,500.

Let the amount invested in the account paying 6% be x. So, the amount invested in the account paying 8% is 1500-x.

Total interest earned by Ming is

At the end of the year, she had earned $106.40 in interest.

Divide both sides by -2.

The value of x is 680, therefore the amount invested in the account paying 6% is 680 and the correct option is B.

2.   2 3/5.

3.   2 1/2.

step-by-step explanation:

6 - 3 2/5

= 6 -   17/5

= 30/5 - 17/5

= 13/5

= 2 3/5 (answer).

5 1/4 - 2 3/4

= 21/4 - 11/4

= 10/4

= 2 1/2 (answer).

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.