In texas, the population of a species of bats is decreasing at a rate of -0.121 per year. the population was 34,000 in 2000. according to the function; a(t) = a0e^(kt), what is the predicted population in 2015?

Population of bats in year 2015 is 5536.

Step-by-step explanation:

The given function A(t) = predicts the population of bats after t years.

Here A(t) = population after 't' years

           k  = growth constant

           t = time in years

          = initial population

In year 2000 population of bats A(t) = 34,000

Since rate of decrease in population k = 0.121 per year

So population in 2015 will be

A(t)

= 34,000 [ ]

= 34,000 ( 0.162837)

= 5536 bats

Therefore, population of bats in year 2015 is 5536.

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b