Tina can paint a room 1.5 times faster than joey can. if they work together, they can paint a room in 6 hours. how long would it take the slower person working alone to paint the room?

To answer this problem, let us define that:

x = amount of time Joey can paint a room in hours

1.5 x = amount of time Tina can paint a room in hours

Each person can complete 1 job in the specified amount of time.

1 job / x hours = rate of Joey

1job / 1.5 x hours = rate of Tina

By adding the two, they can paint the room (1 job) in 6 hours. Therefore:

(1 / x) + (1 / 1.5 x) = 1 / 6

Multiplying whole equation with 6 (x) (1.5 x):

6 (1.5 x) + 6 x = x (1.5 x)

9 x + 6 x = 1.5 x^2

Dividing both sides with x:

15 = 1.5 x

x = 10 hours

Therefore the time it will take Tina, the slower person, is 1.5x = 15 hours

ANSWER: 15 hours

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752