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Mathematics, 05.10.2019 12:30 carapiasebas

Tan x =sin x/cos x. therefore, tan(90-a) =
a) 1/tan(90-a)
b) 1/sin a
c) 1/cos(90-a)
d) 1/tana

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Tan x =sin x/cos x. therefore, tan(90-a) =
a) 1/tan(90-a)
b) 1/sin a
c) 1/cos(90-a...
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