The top of a 16-foot ladder is 2 feet farther up a wall than the foot is from the bottom of the wall. how far is the ladder from the bottom of the wall?

Let x=distance of foot of ladder from the wall, then
x+2=height of top of ladder up the wall.
length of ladder = 16 feet.
Using Pythagoras theorem, 
x^2+(x+2)^2=16^2, expand and simplify
2x^2+4x+4 = 256 again simplify
x^2+2x-126=0  [fail to factor]
apply quadratic equation:
x=(-2+/-sqrt(4+504))/2
=-1+/-sqrt(127)
x=-12.3 (rejected) or
x=10.27 feet from wall.

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!