In the following system of equations, what would you do to eliminate x? 2x + 4y = 10 x - 3y = 12

2x +4y =10x-3y =12

2x +4y =12 eq. 1

10x-3y =12 eq.2

2x =12 -4y [using eq. 1]
x = (12-4y)/ 2
= 6 -2y

Now, substitute the value of x in eq. 2
10 (6-2y)-3y =10
60 -20y -3y =10
-23 y = 10 -60
y = -50 / -23
y = 50/23

Now, substitute this value of y in any equations given above

10 x-3 (50/23) =12
10x - (150/23)= 12
x= 426/230

Dis the answer for this question