Rectangle abcd has vertices a(–6, –2), b(–3, –2), c(–3. –6), and d(–6, –6). the rectangle is translated so that the coordinates of the image are a’(–10, 1), b’(–7,1), c’(–7, –3), and d’(–10, –3). which rule was used to translate the image

It is given in the question that Rectangle ABCD has vertices A(–6, –2), B(–3, –2), C(–3. –6), and D(–6, –6). The rectangle is translated so that the coordinates of the image are A’(–10, 1), B’(–7,1), C’(–7, –3), and D’(–10, –3).

Let's take  A and A'. In A', the  x coordinate moves left by 4 units and the y coordinates ,moves up by 3 units .

So the rules is

(x,y)->(x-4,y+3)

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

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x + 2 + 1/x+5