What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)?

4x-5y=5

5x+4y=37

4x+5y=5

5x-4y=8

4x-5y=5

Step-by-step explanation:

What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)?

4x-5y=5

5x+4y=37

4x+5y=5

5x-4y=8

from the graph given , the slope of a graph becomes

S=y2-y1/(x2-x1)

Slope=10-0/(-8-0)

slope=-10/8

for a line that is perpendicular

perpendicular lines=-1/m

negative inverse of the slope

8/10

equation of the line that passes  through the point (5,3) becomes

y-y1=m(x-x1)

y-3=8/10(x-5)

5(y-3)=4(x-5)

5y-15=4x-20

5y=4x-20+15

4x-5y=5  A

ddd

step-by-step explanation:

0.6

39mph

step-by-step explanation: