Im running out of time me with this? which equation represents the circle described?

the radius is 2 units.
the center is the same as the center of a circle whose equation is x2 + y2 – 8x – 6y + 24 = 0.
(x + 4)2 + (y + 3)2 = 2

(x – 4)2 + (y – 3)2 = 2
(x – 4)2 + (y – 3)2 = 2²
(x + 4)2 + (y + 3)2 = 2²

Well, firstly, the equation of a circle is:
(x-h)^2 + (y-k)^2 = r^2, where the center of the circle is at (h, k), and the radius is = r.
Secondly, since the problem states that the radius is 2, then the equation will be equal to 2^2. That eliminates answers A) and B).
Thirdly, we need to find the center. If we change the sample equation:
x2 + y2 – 8x – 6y + 24 = 0 to:
(x2 - 8x + 16) + (y2 - 6y + 9) - 1 = 0, because 16+9-1 = 24
We see that fits into our circle equation of: (x-4)^2 + (y-3)^2 = 1
Now the center of this circle is at:
(4, 3)
Now the only answer between C) and D) with a center at (4, 3) is:
C) (x – 4)^2 + (y – 3)^2 = 2²
That is your correct answer.