To approach a runaway a plane must be 7 descent starting from the height of 3 miles above the ground. how many miles from the runaway is the airplane at the start of this approach

use SOHCAHTOA 

S = sine

O = opposite edge

H = hypotenuse

T = Tangent

A = adjacent edge

C = cosine.

The extreme is where the runaway is indicated by the hypotenuse is the required distance. Therefore,

sine 7= 3/H

H = 3/sine 7= 24mi

21

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!