The following equation f(x) = x³ + 0.5x² + 4.5 has only 1 real root. it lies between the interval [-1,0].

We are asked in this problem to find the real root of the polynomial f(x) = x3 + 0.5x2 + 4.5. in this case, to find the root of the equation, we equate the equation to zero. 
f(x) = x³ + 0.5x² + 4.5 = 0 
        2x3 + x^2 + 9 = 0
x1=−1.83557
x2=0.66779+1.41619∗i
x3=0.66779−1.41619∗i

answer is -1.84