Point a has an x-coordinate of 7 and lies below the x-axis on a circle with a center at (0, 0) and a radius of 8. to the nearest tenth, what is the y-coordinate for point a? −4.0 −3.9 −3.8 −3.7

the formula of a circle is: x2 + y2 = r2

substituting known values in the formula: x=7 and r=8

72 + y2 = 82

calculating for value of y:

y2=64-49

y=±√15

y=±3.9

since point A lies below the x-axis then

y=-3.9

Answer-

The y-coordinate for point is -3.9

Solution-

Point A has an x-coordinate of 7 and lies below the x-axis (i.e -ve y-coordinate)

Let us assume, the coordinates of the point is (7, y)

The general equation for circle with centre at (h, k) and radius r, is

As here the centre is origin (0, 0) and radius 8, so equation of the circle is

As point A lies on the circle, so it must satisfy the circle equation, so

As the point lies under x axis, so considering only -ve value,

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles