Aprincipal of $4600 is invested at 5.5% interest, annually. how many years will it take to accumulate $7000 or more in the account?

A = 7000
P = 4600
r = 5.5% = 5.5/100 = 0.055
n = 1
t = unknown

A = P*(1+r/n)^(n*t)
7000 = 4600*(1+0.055/1)^(1*t)
7000 = 4600*(1+0.055)^t
7000 = 4600*(1.055)^t
7000/4600 = [4600*(1.055)^t]/4600
1.52173913043478 = 1.055^t
Log[1.52173913043478] = Log[1.055^t]
Log[1.52173913043478] = t*Log[1.055]
Log[1.52173913043478]/Log[1.055] = t
t = Log[1.52173913043478]/Log[1.055]
t = 7.84176002044643

It will take at least 8 years.

Idrk but i think u should figure out the n dia n then the units it will make it way more easier