Complete the square to rewrite y = x2 – 6x + 5 in vertex form. then state whether the vertex is a maximum or a minimum and give its coordinates. a. maximum at (3, –4) b. minimum at (3, –4) c. minimum at (–3, –4) d. maximum at (–3, –4)

B.Minimum at (3, –4)

Step-by-step explanation:

Given is a quadratic function as

Considering the first two terms, we find that if we add 9 we can make it a perfect square

Hence add and subtract 9 to right side

This is in vertex form

Vertex = (3,-4)

Since coefficient of leading term of x is positive, the parabola is open up and hence minimum is at (3,-4)

Option B,

x= 3^y

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4