The length of a rectangle is 5 5 inches more than the width. the perimeter is 26 26 inches. find the length and the width.

Let x = width in
Because the length is 5 in. more than the width, therefore
length = (x + 5) in

The perimeter is equal to twice the width plus twice the length. Therefore
2x + 2(x+5) = 26
2x + 2x + 10 = 26
4x + 10 = 26
4x = 26 - 10 = 16
x = 16/4 = 4

The width is  4 in.
The length is 4 + 5 = 9 in

Width = 4 in
Length = 9 in

I'm just guessing, but my answer would c. 0 to 300.