In a right triangle if one acute angle has a measure of 10 x + 3 and the other has a measure of 3x + 9 find the larger of these two angles

Hello,
Since we're given that both of these angles are acute(less than 90 degrees), we can form these 2 inequalities: and . Isolating x in both inequalities we get:  and . Therefore we have . Now let's form another inequality byadding the 2 original inequalities: . Simplifying we get . Solving for x we get . So now we have .Therefore, x must be positive and for any positive x in this range 10x+3 is greater than 3x+9. Let me know if that doesn't make sense!

Delta airlines or untied airlines