The axis of symmetry for a function in the form f(x) = x2 + 4x − 5 is x = −2. what are the coordinates of the vertex of the graph?
(−9, −2)
(−17, −2)
(−2, −17)
(−2, −9)

Option D

Step-by-step explanation:

The given function is f(x) = x² + 4x - 5

Axis of symmetry is x = -2

Since axis of symmetry of a quadratic function passes through the vertex so x = -2 will be the x-coordinate of the vertex.

We will now convert the given function into vertex form.

Where (h, k) are the coordinates of the vertex

f(x) = x² + 4x - 5

     = x² + 4x + 4 - 4 - 5

f(x) = (x + 2)² - 9

Therefore, the vertex will be (-2, -9)

Option D will be the answer.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

g

step-by-step explanation: