If h(x)= 4x^2-16 was shifted 7 units to the right and 3 down, what would the new equation be? a. h(x)= 4(x+9)^2-17 b. h(x)= 4(x-9)^2-17 c. h(x)= 4(x-7)^2- 19 d. h(x)= 4(x+7)^2 +19

In general,
right shift h is given by
f(x-h)->g(x)
up shift is given by
f(x)+k->g(x)

So for h=7, and k=-3, we have
H(x-7)-3
=4(x-7)²-16-3
=4(x-7)²-19

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!