Acircle centered at (–1, 2) has a diameter of 10 units. amit wants to determine whether (2, –2) is also on the circle. his work is shown below.
the radius is 5 units.
find the distance from the center to (2, –2).

the point (2, –2) doesn’t lie on the circle because the calculated distance should be the same as the radius.

Amit's mistake : The point (2, –2) doesn’t lie on the circle because the calculated distance should be the same as the radius.

Step-by-step explanation: Given center of the circle (-1,2) and diameter 10 units and a point (2,-2).

Radius of the circle is half of the diameter.

So, the radius = 10/2 = 5.

Therefore, first step Amit applied is correct.

Second step is also correct to check if the distance between center (-1,2) and given point (2,-2) is same as length of radius.

Let us check what is the distance between enter (-1,2) and given point (2,-2).

In third step, Amit didn't find equal distance between center (-1,2) and given point (2,-2) same as radius 5.

But it is same.

the answer is 45 i just did it on oddesy ware

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3