Acylinder cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. what is the approximate volume of the tube? round to the nearest whole cubic centimeter.

1005 cm³ will be the volume of the cylinder cardboard tube.

Step-by-step explanation:

Diameter of a cylinder cardboard tube = 8 cm

Therefore radius = 4 cm.

Height of the cylinder cardboard tube = 20 cm.

Now we have to calculate the volume of the tube

As we know the formula of the volume of cylinder is

V = πr²h

V = π (4)²(20) = 320π cm³

Now we put the value of π as 3.14

Volume = 3.14×320 = 1004.80 ≈ 1005 cm³

Therefore Volume of the cylinder cardboard used to package a gift will be = 1005 cm³

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.