(y+3) (y^2-3y+9) what is the product? y3 + 27 y3 – 27 y3 – 6y2 + 27 y3 + 6y2 + 27
a y3 + 27

b y3 – 27

c y3 – 6y2 + 27

d y3 + 6y2 + 27

 A is the answer hope this helps

The correct answer is:  [A]:  " y³ + 27 " .

Explanation:

 (y + 3) (y² − 3y + 9) =

y*y²  = y³

-3y *y  =  − 3y²
 
+9*y = + 9y

  =  (y³  −  3y²  +  9y) ;

+3*y² =  + 3y²

-9*y =  − 9y

(+3)*(+9) =  + 27

  =  (3y²  −  9y  +  27) ;


→   (y + 3) (y² − 3y + 9) = 

      (y³  −  3y²  +  9y)  +  (3y²  −  9y  +  27)  =

         y³  −  3y²  +  9y  +  3y²  −  9y  +  27  = ?

Combine the "like terms":

y³ ;

− 3y² + 3y² = 0 ; [cancel out] ; 

+ 9y − 9y = 0 ; [cancel out] ;

+ 27 ;

to get:

    " y³ + 27 " ;

  →  which is:  Answer choice  [A]:  " y³ + 27 " .

Peanuts r great aren’t they it just has a good taste