Radar tracking station o is 40 km away from a ship at point a. the ship travels east 45 km to point c at 30km/h. how long will the ship be on the radar with a 20 km radius?

From the given figure, segment OA = 40km, segment AC = 45km and segment OC = 20km
Angle OAC = 21 degrees.

Now, angle OBC = angle OCB because they are the angle formed at the intersection of the radius and the chord of a circle.

Using, sine rule, we find angle OCB.

Recall that sine rule states that


Thus,


Segment BC is a chord which makes angle 45.79 with the radius of the circle,
Using Pythagoras theorem, we have


Recall that time of a body travelling a distance, d, at v km/h is given by


Given that the ship travels at 30km/h, the time the ship will take on the radar covelling a distance of 27.89km is given by

The answer is 225 miles per 4.5 hours. hope this ; )

Hello!
volume of sphere =4/3.pi.r^3