The current size of an image on sandra's computer is shown below:

a rectangle is shown. the length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

what are the dimensions of the image at fraction 1 over 2 times its current size?

a. length = 4 inches, width = 6 inches
b. length = 3 inches, width = 4 inches
c. length = 8 inches, width = 10 inches
d. length = 12 inches, width = 16 inches

Option B is correct

Length = 3 inches, width = 4 inches

Step-by-step explanation:

As per the statement:

The current size of an image on Sandra's computer is shown below:

A rectangle is shown:

The length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

⇒Length(l) = 6 inches and width(w) = 8 inches

We have to find the dimension of the image at fraction 1 over 2 times its current size.

Dimensions of the image at

then;

inches

and

inches

Therefore, the dimensions of the image at fraction 1 over 2 times its current size are:

Length = 3 inches, width = 4 inches

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic