An acute angle θ is in a right triangle with cos θ = two thirds. what is the value of sec θ?

 the required value is

Step-by-step explanation:  Given that an acute angle θ is in a right triangle with cos θ = two thirds.

We are to find the value of sec θ.

In a right-angled triangle, we have the following relation between the cos and sec of an acute angle θ :

From the given information, we have

Therefore, we get

Thus, the required value is

no idea

step-by-step explanation:

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.