Tasha assembled a picture frame that is advertised as rectangular. the completed frame is 14 inches long and 10 inches wide. she measured the diagonal length across the frame as 20 inches. which best explains why the frame cannot actually be rectangular?

the diagonal of a rectangle is square root of (w^2 +l^2)

so square root of (14^2 +10^2) = 17.2 inches

since 20" is longer than 17.2 it can't be a rectangle

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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5

step-by-step explanation: