Acertain group of women has a 0.61% rate of red/green color blindness. if a woman is randomly selected, what is the probability that she doesn't have red/green blindness? what is the probability that the woman selected does not have red/green color blindness?

99.39%

Step-by-step explanation:

Given : A certain group of women has a 0.61% rate of red/green color blindness.

We can write 0.61%= 0.0061 [by dividing it by hundred]

Let E be the event of a woman has red/gree.n blindness

Then, the probability that a woman has red/green blindness :

P(E)= 0.0061

Now, there are only two possible events , one is "E" and the other is "E not" .

Hence, the probability that the woman selected does not have red/green color blindness = 0.9939=99.39%

a

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.