Ajar contains 8 nickels, 10 dimes, 12 quarters, and 22 pennies. a coin is chosen at random from the jar. what is the probability that the coin chosen is a penny? question 11 options:

The required probability is 42.30%.

Step-by-step explanation: We are given that a jar contains 8 nickels, 10 dimes, 12 quarters, and 22 pennies. a coin is chosen at random from the jar.

We are to find the probability that the coin chosen is a penny.

Let S denotes the sample space for experiment of selecting a coin of the jar and A denotes the event that the randomly selected coin is a penny.

Then,

n(S) = 8 + 10 + 12 + 22 = 52     and    n(A) = 22.

Therefore, the probability of event A is given by

Thus, the required probability is 42.30%.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752