The proof that δefg ≅ δjhg is shown.
given: g is the midpoint of hf, ef ∥ hj, and ef ≅ hj.
prove: δefg ≅ δjhg
statement
reason
1. g is the midpoint of hf 1. given
2. fg ≅ hg 2. def. of midpoint
3. ef ∥ hj 3. given
4. ? 4. alt. int. angles are congruent
5. ef ≅ hj 5. given
6. δefg ≅ δjhg 6. sas
what is the missing statement in the proof?
a. ∠feg ≅ ∠hjg
b. ∠gfe ≅ ∠ghj
c. ∠egf ≅ ∠jgh
d. ∠gef ≅ ∠jhg

SAS Postulate:  If two sides and the included angle of the first triangle are congruent to the corresponding parts of the second triangle, then the correspondence is a congruence.

You have:

So if you want to use SAS Postulate you have to prove that ∠EFG≅∠JHG. These angles are alternate interior angles at parallel lines EF and GH (given that they are parallel in step 3) and transversal FH.

Thus,

Therefore, you can use SAS in step 6.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation: