Afarmer builds a rectangular pen with a perimeter of 116 feet. if the length is 5 feet more than the width, what is the width? a. w + 5 = 116 b. 4w + 10 = 116 c. 2w + 5 = 116 d. 2w + 10 = 116

The answer is B. 4W+10=116

Step-by-step explanation:

In order to determine the width, we have to define both variables: width and length.

L=length of the rectangular pen.

W=width of the rectangular pen.

We know that length is 5 feet more than the width, so:

L=W+5

Also we know that the perimeter of a rectangle is:

P=2L+2W

Then, we want to solve for width variable. We replace the value of the perimeter and the expression of L in function of W.

P=116

2L+2W=116

2(W+5)+2W=116

2W+10+2W=116

4W+10=116

Finally, the correct option is B. 4W+10=116

the answer is (2x+8)²= 16