Frank kicks a soccer ball off the ground and in the air, with an initial velocity of 30 feet per second. using the formula h(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?

A quadratic equation is in the form of then the axis of symmetry is given by:

Given the equation:

where,

v is the initial velocity

s is the initial height.

Frank kicks a soccer ball off the ground and in the air, with an initial velocity of 30 feet per second.

⇒feet per second.

Substitute in [1] we have;

            ....[1]

then:

the axis of symmetry is:

sec

Substitute in [1]  we have;

⇒

⇒  feet

Therefore,the maximum height the soccer ball reaches is, 14.1 feet

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

i think u have 12 apples sorry again i don't really know if it correct i'm just tryna hrlp people out.