Claire’s mother is 4 years more than twice claire’s age. the sum of their ages is 58 years. claire’s age is years, and her mother’s age is years

Answer with explanation:

Let Claire's age = x years

Age of Claire's mother =(2 x +4 ) years

Sum of the ages of Claire and her mother =58 years

If we write the above statement in terms of equation , it will be

⇒ x + 2 x +4=58

⇒3 x +4=58

⇒3 x =58 -4

⇒3 x =54

Dividing both side by , 3 , we get

→x=18

Claire's age = 18 years

Age of Claire's mother =(2 x +4 )=2×18+4=36+4=40 years

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb