What translation was used on abcd to produce a'b'c'd'?

First of all, we need to know the coordinate of ABCD and A'B'C'D', so the coordinate of ABCD will be:
A(-3,5)
B(-1,2)
C(-2,-1)
D(-5,-3)
Then, coordinate of new figure will be:
A'(-7,8)
B'(-5,5)
C'(-6,2)
D'(-9,0)
Next,
Let's try all the translations:
(x,y) to (x+4,y+3)
A(-3,5) to A'(-3+4, 5+3)
A(-3,5) to A'(1,8)
Which is not right because A' need to be (-7,8)
(x,y) to (x-4,y+3)
A(-3,5) to A'(-3-4,5+3)
A(-3,5) to A'(-7,8)
B(-1,2) to B'(-1-4,2+3)
B(-1,2) to B'(-5,5)
C(-2,-1) to C'(-2-4,-1+3)
C(-2,-1) to C'(-6,2)
D(-5,-3) to D'(-5-4,-3+3)
D(-5,-3) to D'(-9,0)
Yay, we found the answer. As a result, (x,y) to (x-4,y+3) is your final answer. Hope it help!